You would use that equation to find out the concentration of your final solution, since we know the volume and concentration of our first mixture. 1.5 qts= 0.375 gal. and we know our final volume (10 gallons), so we want to discover what that final concentration in the 10 gallons is. So the setup is (.03)(.375)=(x)(10). which comes out to a final concentration of .001125. times by 100 and .1125 % is our final answer.
Gregor
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Jul 02 at 03:19 PM
Gregor You just have to be sure all the units of measurement are the same when using m1v1=m2v2 and define what variable you are actually searching for. Also, that equation mainly deals with Molarity as the concentration factor and percentages don't always translate nicely to the actual chemical concentration based on moles/per liter of solution. Another way to solve for it would be to calculate out the grams of water in 1.5 quarts. Then with total grams X by .03 to get 3 percent of the weight of that solution. This 3 percent in grams is how much hydrogen peroxide exists in the solution and will eventually exist in the 10 gallons of water. So then you can just divide that grams of hydrogen peroxide by 10 gallons of water in grams and this will give you the percentage of hydrogen peroxide in that total 10 gallons of water. Which comes out to .134 % which would be your true final percentage if calculating by weights instead of percentages. I can post the math if you wanna visual it.